Half-Life Calculator

Find the remaining quantity, half-life, decay constant, or mean lifetime of a decaying substance.

Six linked quantities and seven time scales, from seconds to years.

Updated October 16, 2026
Frank Zhao - Creator
CreatorFrank Zhao
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Introduction

Anything that decays at a rate proportional to how much is left can be described with a single number: its half-life. Tritium in groundwater, a drug clearing from the bloodstream, a pollutant breaking down in soil — they all follow the same curve, and the half-life says how fast.

This calculator works that curve in both directions. Give it a starting amount, a half-life and a span of time, and it returns what is left. Give it a pair of measured amounts and the time between them, and it returns the half-life that fits. It also carries the two other ways of writing the same rate — the decay constant λ\lambda and the mean lifetime τ\tau — so you can move between a handbook value, a measurement and a rate constant without leaving the page.

The definition behind all of it is the one the US EPA gives for radioactive half-life: the time required for half of the radioactive atoms present to decay. Half of what is there now, not half of what you started with — which is why a substance's half-life does not depend on how much of it the sample holds.

7 time scales

Seconds to years, with months and years on the Julian calendar

N(0)×2−t/TN(0) \times 2^{-t/T}

The whole calculation: a fraction of the starting amount

6 of 6

Every box can be the one the calculator solves for

One rate, three names

A half-life of 12.3 years, a decay constant of 0.0564 per year and a mean lifetime of 17.7 years are not three different facts. They are the same rate, and the calculator will fill in whichever two you leave empty. If a paper quotes a rate constant instead of a half-life, you do not need a separate conversion — put it in the decay constant box.

Quick start

1

Decide what you are measuring

The two quantity boxes accept any consistent measure of the same substance: grams, becquerels, moles, or a raw count of nuclei. Because the calculation uses only the ratio between them, both boxes must describe the same kind of measurement. If you have a weighed mass and want an absolute number of atoms instead, the moles to atoms converter turns one into the other.

2

Enter the half-life — or leave it empty

Type the substance's half-life if you know it. Leave the box empty if it is the value you are trying to find; the calculator re-solves for it as soon as the other three boxes hold numbers.

3

Enter the elapsed time

How long the decay has been running — a span of time, not a calendar year. It reads on the same seven scales as the half-life, so a period recorded in weeks can sit next to a half-life quoted in years.

4

Read the box you left empty

The remaining quantity appears as soon as the inputs are complete. Any one of the six boxes can be the empty one: type a measured amount that is left, and the calculator reports the half-life, the elapsed time or the rate instead.

Worked example: two half-lives of tritium

Tritium has a half-life of 12.3 years, so a 24.6-year span covers exactly two of them. Start with 8 grams of tritiated water, give the half-life and the span in years, and let the remaining amount be the answer:

N(t)N(t)==N(0)×2−t/TN(0) \times 2^{-t/T}==8×2−24.6/12.38 \times 2^{-24.6/12.3}==8×0.258 \times 0.25==2 g2\ \mathrm{g}

What the answer means

Two grams is what the page reports, and it is a quarter of the starting amount because two half-lives have passed: 8 g → 4 g → 2 g. The same arithmetic reads in the other direction too — the activity of that sample falls by the same factor, so a counter that read 800 counts per minute at the start reads about 200 after 24.6 years. The elapsed time does not have to be a whole number of half-lives; 5 years gives 0.754 of the starting amount, for instance.

The decay law and what it assumes

One equation carries the whole page. The amount left is the starting amount scaled by a power of two:

N(t)=N(0) ×2−t/TN(t) = N(0)\,\times 2^{-t/T}

Written with the rate instead of the half-life, the same curve is an exponential in λ\lambda, which is how it usually appears in physics and kinetics:

N(t)=N(0) e−λtλ=ln⁡2TN(t) = N(0)\,e^{-\lambda t} \qquad \lambda = \frac{\ln 2}{T}
N(0)N(0)The amount at the start, in whatever unit you are measuring
N(t)N(t)The amount left after the elapsed time, in the same unit
TTThe half-life: the span that removes half of what is present
ttThe elapsed time — a duration, not a date
λ\lambdaThe decay constant: the chance per unit time that one nucleus decays
τ\tauThe mean lifetime: the average time a single nucleus survives

The constant is a probability, not a countdown

λ\lambda is the rate at which any one nucleus is expected to decay, so a sample of NN nuclei produces activity A=λNA = \lambda N. That is why the same number appears both in counting experiments and, for a first-order chemical reaction, as the rate constant k=ln⁡2/t1/2k = \ln 2 / t_{1/2}; the rate constant calculator covers reaction orders beyond the first.

Every direction the page solves

  • Forward: a starting amount, a half-life and a span give the amount left.
  • Back to the starting amount: N(0)=N(t) 2 t/TN(0) = N(t)\,2^{\,t/T} — what a sample must have contained to read the way it does today.
  • Back to the half-life: T=t ln⁡2ln⁡ ⁣(N(0)/N(t))T = \dfrac{t\,\ln 2}{\ln\!\left(N(0)/N(t)\right)} — the measurement direction, and the one a lab uses to characterise an unknown nuclide.
  • Back to the elapsed time: t=T ln⁡ ⁣(N(0)/N(t))ln⁡2t = \dfrac{T\,\ln\!\left(N(0)/N(t)\right)}{\ln 2} — how long the sample has been decaying.
  • Between the three rate descriptions: half-life, decay constant and mean lifetime are filled in from each other in both directions.

Half-lives span fourteen orders of magnitude

The scale of TT is what makes the seven time scales useful. Tritium sits at 12.3 years, while uranium-238 is measured in billions of them — the EPA lists 4.47 billion years for U-238, 700 million for U-235 and 244,000 for U-234. Enter either value in the half-life box, and give the elapsed time on the same scale or on another one: the calculator normalises both before it evaluates the power, so mixing a half-life in years with a span in seconds is safe.

Units and scales

The time boxes share one set of seven scales with exact definitions: 1 minute = 60 s, 1 hour = 3,600 s, 1 day = 86,400 s, 1 week = 604,800 s, 1 month = 2,629,800 s and 1 year = 31,557,600 s, where the year is the Julian year of 365.25 days and a month is a twelfth of it. The decay constant is offered on the reciprocal of those scales, because a rate is per unit time: a half-life of 12.3 years is λ=0.05635 yr−1=1.786×10−9 s−1\lambda = 0.05635\ \mathrm{yr^{-1}} = 1.786 \times 10^{-9}\ \mathrm{s^{-1}}, the same physical rate written two ways.

Worked examples

Three situations that use different parts of the page. Every result is the value the calculator returns for those inputs.

Measuring a half-life from two readings

A lab counts a tritiated water sample twice: 8.0 units of activity on the first day, 6.0 units five years later. The half-life is the unknown, so leave it empty:

TT==t ln⁡2ln⁡ ⁣(N(0)/N(t))\frac{t\,\ln 2}{\ln\!\left(N(0)/N(t)\right)}==5×0.6931ln⁡(8/6)\frac{5 \times 0.6931}{\ln(8/6)}==12.05 years12.05\ \mathrm{years}

The answer comes back as 380,177,695 seconds when the half-life box is on the seconds scale, which is the same 12.05 years. It also lands about 2% below tritium's accepted 12.3 years — close enough to confirm the sample, not precise enough to redefine the nuclide, which is exactly how a two-point measurement behaves. With the half-life known, the page reports the matching rate on the same screen: λ=1.82×10−9 s−1\lambda = 1.82 \times 10^{-9}\ \mathrm{s^{-1}} and τ=17.38 years\tau = 17.38\ \mathrm{years}.

Reading the rate instead of the half-life

Enter tritium's 12.3-year half-life on its own and the two rate boxes fill themselves in:

λ\lambda==ln⁡2T\frac{\ln 2}{T}==0.693112.3\frac{0.6931}{12.3}==0.05635 yr−10.05635\ \mathrm{yr^{-1}}
τ\tau==Tln⁡2\frac{T}{\ln 2}==12.30.6931\frac{12.3}{0.6931}==17.75 years17.75\ \mathrm{years}

The mean lifetime is longer than the half-life — always, by a factor of 1/ln⁡2≈1.4431/\ln 2 \approx 1.443. Half of a sample is gone by 12.3 years, but the atoms that survive keep surviving, and averaging over that long tail pushes the mean out to 17.75 years. Both numbers describe the same sample; use the half-life for "when is half of it gone" and the mean lifetime when a model expects an exponential time constant.

A half-life longer than the age of the Earth

Uranium-238 has a half-life of 4.47 billion years. Give it 1 kilogram and a span of one million years, and almost nothing appears to happen:

N(t)N(t)==1×2−106/4.47×1091 \times 2^{-10^6/4.47\times 10^9}==0.99984 kg0.99984\ \mathrm{kg}

About 0.16 grams of that kilogram has decayed. The elapsed time is only 0.000220.00022 half-lives, so the ratio barely moves — which is why long-lived nuclides survive in the crust at all, and why a meaningful measurement on one needs a span comparable to its half-life rather than a human one. The same page reports its rate as λ=4.9×10−18 s−1\lambda = 4.9 \times 10^{-18}\ \mathrm{s^{-1}}, a reminder that a small rate constant and a long half-life are two readings of the same fact.

Tips and pitfalls

Check which time scale a rate is quoted on

Rate constants travel badly: 0.0564 yr−10.0564\ \mathrm{yr^{-1}} and 1.79×10−9 s−11.79 \times 10^{-9}\ \mathrm{s^{-1}} are the same decay, and someone comparing the first against a per-second table will conclude the process is millions of times faster than it is. Before trusting a comparison, write both rates on the same scale.

A model expecting a time constant wants the other box

Plenty of formulas are written as e−t/τe^{-t/\tau}, with the exponential time constant underneath. Handing that model a half-life instead makes the decay it predicts about 44% too fast, because the two differ by a factor of ln⁡2\ln 2. When a formula asks how long until half is gone, use the half-life; when it expects a time constant, use the mean lifetime.

Guard the elapsed time, not the masses

The half-life recovery divides by the logarithm of the ratio, so a small error in the ratio matters far less than an error in the span. On the 8.0 → 6.0 pair above, five years gives 12.05 years but six years gives 14.46 — a one-year slip moves the answer by about 20%. Nail down the dates before you refine the measurements.

Quote the answer at the precision of your data

A half-life recovered from two readings carries the error of both of them, and a span rounded to whole years adds more. If the two measurements are good to a few percent, then a half-life with five significant digits is claiming accuracy the experiment does not have. Round the answer to match the inputs before you write it down.

The arithmetic is exact; the sample is not

The curve describes the average behaviour of an enormous number of nuclei. Each one decays at a random moment, so a sample holding a handful of atoms will not lose exactly half of them in one half-life — it might lose more, fewer, or all of them. The law sharpens as the sample grows, and real counting statistics add their own uncertainty on top of it.

Questions

Q

Can I use this for something that decays without being radioactive?

Yes, as long as the rate is proportional to the amount present. Drug elimination, pollutant breakdown, and the loss of a reactant in a first-order chemical step all follow the same curve, and their half-lives are read the same way. It stops applying when the process saturates — when the body or the catalyst can only clear so much per hour, the rate stops scaling with the amount left and the tail flattens away from this curve. If your quantity is growing rather than shrinking, the same law applies with the sign of the exponent flipped, which is what the doubling time calculator handles.

Q

Why did the half-life stay blank, or a box turn red?

Blank means that direction has no answer for the numbers given. The common case is a starting and remaining amount that are equal: no decay has happened between them, the ratio is 1, its logarithm is 0, and dividing by it is undefined. Enter a pair that actually differs, or supply the half-life yourself.

Red means the number exists but breaks a real boundary. Every box must be greater than zero, and a remaining amount larger than the starting amount is not decay at all — the page flags it rather than reporting a negative half-life or a negative elapsed time. A quantity that falls to exactly zero is also rejected: the model approaches zero without ever reaching it in finite time.

Where the model stops

  • One nuclide, one decay path. The formula is a single exponential, so it describes a substance that decays one way. Many heavy nuclides decay in chains, where the daughter is itself radioactive: the parent's atoms fall on this curve, but the sample's total activity is continuously replenished by its daughters and does not.
  • A pair of readings measures one effective rate. If a sample holds a mixture of nuclides, or the rate changes during the window, two points still produce one half-life — but it describes the average behaviour over that interval, not either component. Sample again at a different interval and the answer will move.
  • Measurements set the accuracy, not the arithmetic. The calculation is exact for the numbers typed in. Background counts, calibration drift, a span rounded to whole years and a sample that is not what the label says all land in the result, and a half-life recovered from two points carries the error of both of them.
  • Not a basis for radiation protection decisions. Working with radioactive material, planning shielding, disposing of waste or reporting activity is governed by your facility's procedures and the relevant regulator. This page is an educational and planning tool; use it to understand the decay, then confirm against measured data and official guidance before acting on it.
Half-Life Calculator - Decay Time, Remaining Quantity and Rate