Aluminum Weight Calculator

Estimate how much an aluminum part weighs from its shape, alloy and size.

Covers 14 aluminum alloys and 11 stock shapes, with metric and imperial units.

Updated October 20, 2026
Frank Zhao - Creator
CreatorFrank Zhao
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Overview

Aluminum is ordered by size but paid for by weight, and the gap between the two is widest on exactly the pieces people ask about: plate, bar, tube, wire and can stock. This page closes that gap for eleven stock shapes. Pick the alloy, pick the shape, type the dimensions you measured, and it returns the mass of one piece or of the whole batch.

Three jobs bring people here, and all three use the same screen:

  • Weigh stock before you handle it. A plate, a bar or a length of tube, in kilograms or pounds, before it is picked up, loaded or booked onto a van.
  • Price a batch instead of a piece. Set the number of pieces and the result is the total mass, which is the figure a freight quote or a scrap ticket asks for.
  • Go the other way. Start from a target mass and let a dimension or the piece count be solved for. That is how a job that says “45 kg of 50 mm tube” turns into an actual cut length.

The alloy menu supplies the density, so you never have to look a material constant up separately. Each dimension carries its own unit menu, so a length in feet and a thickness in millimetres can be entered side by side without converting anything by hand, and the answer can be shown in grams, kilograms, ounces, pounds, stones or tons.

The number is mass, which the trade calls weight. Kilograms and pounds describe how much aluminum there is, and that is what a scale at the yard reports. Weight in the strict physical sense is a force: a kilogram of aluminum presses down with about 9.81 N\,9.81\ \mathrm{N} on Earth and roughly a sixth of that on the Moon, while the mass is unchanged. For buying, shipping and machining, mass is the number that matters.

How to Use

1

Choose the alloy

The Alloy menu sets the density used by the calculation, and the density is shown underneath it in kilograms per cubic meter. Aluminum (average) at 2700 kg/m³ is the sensible choice when the grade is unknown; pick the exact grade when the drawing or the stock tag names one.
2

Choose the shape that matches the piece

Eleven entries cover plate and bar, round and polygon bar, ring sections, wire, tube, sphere, torus rings, cans and a catch-all volume. Every box in the Dimensions group changes with the shape, so the only fields on screen are the ones the chosen shape actually needs.
3

Type the dimensions you measured

Each box has its own unit menu. Lengths and widths default to metres and offer centimetres, decimetres, inches, feet, yards, feet plus inches, and metres plus centimetres. Thickness opens in metres and adds millimetres, kilometres and thousandths of an inch.
4

Set how many pieces, then read the mass

The count starts at one. The result box shows the total for all pieces, in kilograms by default, and its own unit menu converts that figure to grams, ounces, pounds, stones, metric tons, US short tons or imperial tons.

One plate, two pieces

Take a 6063 plate — 2700 kg/m³, the same nominal density as the average aluminum entry — that measures 1 m by 50 cm and is 10 mm thick, in two pieces. Enter the thickness as 10 mm and the other two in metres, then set the count to 2:

V=1×0.5×0.01V = 1 \times 0.5 \times 0.01==0.005 m30.005\ \mathrm{m^3}
m=0.005×2,700×2m = 0.005 \times 2{,}700 \times 2==27 kg27\ \mathrm{kg}

That is 13.5 kg per plate, and 27 kg for the pair — about 59.5 lb, which the result box will show if its unit menu is switched to pounds. The mass on screen always belongs to the whole batch, so check the count before quoting a number.

Calculation Method

Every shape answers the same one-line question:

W=V×ρ×nW = V \times \rho \times n

where WW is the mass of the batch, VV is the volume of one piece, ρ\rho is the alloy density and nn is the number of identical pieces. Only the volume changes from one shape to the next:

Shape in the menuVolume of one piece
Rectangular prism (plate)L×w×tL \times w \times t
Circular prismπr2t\pi r^{2} t
Hexagonal prism332 s2t\tfrac{3\sqrt{3}}{2}\, s^{2} t
Octagonal prism2(1+2)s2t2\left(1+\sqrt{2}\right) s^{2} t
Ring prismπ(R2−r2)t\pi\left(R^{2}-r^{2}\right) t
Wireπr2L\pi r^{2} L
Tubeπ(R2−r2)L\pi\left(R^{2}-r^{2}\right) L
Sphere43πr3\tfrac{4}{3}\pi r^{3}
Ring (torus)π24(R+r)(R−r)2\tfrac{\pi^{2}}{4}\left(R+r\right)\left(R-r\right)^{2}
Other prismsthe volume you supply

The can is the one shape with two parts, and the two parts are weighed differently. The wall is a hollow cylinder, the wall thickness is the difference between the two radii, and the base is a solid disc of the inner radius over the base height:

Vcan=V_{\mathrm{can}} =πh(R2−r2)\pi h\left(R^{2}-r^{2}\right)++πr2hb\pi r^{2} h_{\mathrm{b}}

A lid is a full disc of the outer radius, laid on top of that:

Vlid=V_{\mathrm{lid}} =VcanV_{\mathrm{can}}+πR2hl+ \pi R^{2} h_{\mathrm{l}}

The same statement, read backwards

Because the mass, the density and the count are one product, any single unknown can be recovered from the rest:

  • A missing volume or a target mass: V=W/(ρ n)V = W / (\rho\,n).
  • A missing dimension, once the volume is known. The plate divides (its length is L=V/(w t)L = V / (w\,t)); the circular prism, hexagonal prism, octagonal prism, ring prism and wire take a square root, such as r=V/(πL)r = \sqrt{V / (\pi L)} for the wire; the sphere takes a cube root, r=3V/(4π)3r = \sqrt[3]{3V / (4\pi)}.
  • The count itself: n=W/(ρ V)n = W / (\rho\,V), which answers how many pieces make up a given mass.
  • The density is deliberately not one of them. It is a property of the alloy you selected, so the Density row is read-only and follows the Alloy menu.

Every entry is normalised before it multiplies

The multiplication needs one scale, so each entry is converted first: lengths to metres, volumes to cubic metres, density to kilograms per cubic meter and the result to kilograms, before it is shown in whichever mass unit is selected.

xbase=x_{\mathrm{base}} =xentered×funitx_{\mathrm{entered}} \times f_{\mathrm{unit}}

The imperial factors are exact definitions rather than rounded table values: an inch is 0.0254 m, the international foot is 0.3048 m and the avoirdupois pound is 0.45359237 kg, which is why a conversion never introduces an error of its own. The inch, foot and yard definitions are set out in the NIST Guide to the SI, Appendix B.

Alloy Densities

Fourteen entries sit in the Alloy menu. The differences look small in absolute terms — the whole menu spans 2600 to 2800 kg/m³ — but they are real, and they move the answer by the same percentage as the density moves.

Alloykg/m³g/cm³
Aluminum (average)27002.70
Melted aluminum26002.60
Aluminum 105027102.71
Aluminum 110027202.72
Aluminum 310327302.73
Aluminum 500527002.70
Aluminum 508326502.65
Aluminum 525126902.69
Aluminum 545426902.69
Aluminum 575426602.66
Aluminum 600527002.70
Aluminum 606327002.70
Aluminum 608227002.70
Aluminum 707528002.80

The spread is worth paying attention to when the mass itself is the deliverable. The lightest wrought entry, 5083 at 2650 kg/m³, and the heaviest, 7075 at 2800 kg/m³, differ by about 5.7%\,5.7\%, so the same plate weighs five or six percent more in one than in the other. Guessing the alloy is fine for a rough handling figure and less fine for a freight booking.

The values are nominal figures for each designation, not a measurement of your piece. Real stock varies with the exact composition within the grade specification, with temper, and with the thickness and width tolerances the mill rolls to. Treat a result as typical for that alloy rather than certified for the bar in your hand.

Two entries deserve a word. Melted aluminum at 2600 kg/m³ is liquid metal, so it is there for melt and casting estimates, not for a solid billet.Aluminum (average) is the right fallback when the grade is unknown: it is the value the menu opens on, and it sits in the middle of the range.

The Density row is read-only because the alloy owns it, but its unit menu still works: switch it to g/cm³, lb/ft³ or lb/in³ and the same density is re-expressed. If your datasheet quotes a scale that is not in that menu, convert it first with the density conversion calculator.

Working Back from a Target Weight

Type a target mass into the result box and the page solves for whatever else is still free. Which box gives way follows a simple rule, and knowing the rule saves a lot of retyping.

  • Numbers you typed win. A dimension, count or mass you entered is treated as a measurement you are sure of.
  • The count gives way first. Until you set the count yourself it is the default of one, so it is the first quantity to be solved, and the answer reads “this is how many pieces reach that mass”.
  • Then the first dimension of the shape. For a plate that is the length, for round bar the radius, for a tube the length, for a can the wall height.

A target mass on the plate from above

Start from a 1 m × 0.5 m plate, 10 mm thick, at 2700 kg/m³ — one piece weighs 13.5 kg — and ask for 27 kg. The plate dimensions are measurements, so the count is what changes: two pieces. Fix the count at three instead, and the length becomes the answer:

L=270.5×0.01×2,700×3L = \frac{27}{0.5 \times 0.01 \times 2{,}700 \times 3}==0.667 m0.667\ \mathrm{m}

Every mass, count and dimension that results from a target is marked as a solved value while you work, so you can tell your own figures from the ones the page supplied.

A cut length of tube

A 50 mm outside diameter tube with a 2 mm wall weighs 0.8143 kg per metre. Pin the count at one, then ask for 1 kg: the length comes back as 1.228 m, which is the number to set on the saw. Leaving the count on its default would have answered a different question — how many one-metre lengths weigh 1 kg.

Where the ring is different

The torus volume is a cubic in either radius, so the ring does not offer a radius solution from a target mass. The count absorbs the target instead: 5 kg of rings that weigh 2.498 kg each comes back as 2.001 pieces. Read that as “two rings are 4.996 kg, and you need a third to reach 5 kg” rather than as a fraction of a ring, and round the count up for an order.

A target that the geometry cannot reach is not silently rounded. Give a ring prism with a 2 cm outer radius and a 10 mm thickness a 100 kg target and the bore stays blank with an explanation, because no bore would make a disc of that diameter and thickness weigh 100 kg. In the same way, a bore wider than the outside turns both radius boxes red while leaving the numbers visible, so an impossible measurement is flagged rather than hidden.

Worked Examples

A 4 by 8 sheet of quarter-inch plate

A common sheet size is 4 ft by 8 ft, and quarter-inch plate is 6.35 mm. At 2700 kg/m³:

V=1.2192×2.4384×0.00635V = 1.2192 \times 2.4384 \times 0.00635==0.018878 m30.018878\ \mathrm{m^3}
W=0.018878×2,700W = 0.018878 \times 2{,}700==50.97 kg50.97\ \mathrm{kg}

About 51 kg, or 112.4 lb — heavy enough that the route from the rack to the bench is worth planning before the sheet comes off it. The same page with the count set to five answers the pallet question directly.

A ring, measured the way a ring is measured

A ring with a 10 cm outer radius and a 5 cm hole. The formula above uses those two measured radii directly, so there is nothing to convert: the tube of the ring has a 2.5 cm radius, and its centre line sits 7.5 cm from the middle.

V=π24V = \frac{\pi^{2}}{4}×0.15\times 0.15×0.052\times 0.05^{2}==9.2528×10−4 m39.2528 \times 10^{-4}\ \mathrm{m^3}
W=9.2528×10−4×2,700W = 9.2528 \times 10^{-4} \times 2{,}700==2.498 kg2.498\ \mathrm{kg}

Written as a general torus, the same volume is 2π2ab22\pi^{2}ab^{2} with a=(R+r)/2a = (R+r)/2 and b=(R−r)/2b = (R-r)/2. If a drawing gives you those two numbers instead, halve their sum and difference to recover the inner and outer radius before entering them.

A can with and without its lid

A 12 cm tall can with a 4 cm inner radius, a 4.5 cm outer radius, a 2 mm solid base and a 1 mm lid:

Vcan=V_{\mathrm{can}} =π×0.12×(0.0452−0.042)\pi \times 0.12 \times \left(0.045^{2} - 0.04^{2}\right)++π×0.042×0.002\pi \times 0.04^{2} \times 0.002==1.702743×10−4 m31.702743 \times 10^{-4}\ \mathrm{m^3}
W=1.702743×10−4×2,700W = 1.702743 \times 10^{-4} \times 2{,}700==0.4597 kg0.4597\ \mathrm{kg}

The same can with a 1 mm lid is 0.4769 kg, so the lid alone adds about 17 g. On a thin-walled can the closure is not a rounding detail: it is a few percent of the total, and the lid is weighed as a disc of the outer radius, the widest part of the can.

Measurement Tips

  • The diameter and side-length boxes have no millimetre entry. Those rows use the general length menu, which runs centimetres, decimetres, metres, inches, feet, yards, feet plus inches, and metres plus centimetres. A 50 mm outside diameter is 5 cm, and a 0.0254 m diameter is exactly one inch. If you are converting a millimetre drawing, the length converter is quicker than doing it in your head.
  • The Thickness box opens in metres. Sheet is normally quoted in millimetres, so switch that row to millimetres and type 3, not 0.003. A thickness entered on the wrong scale is an easy way to be out by a factor of a thousand.
  • A mil is a thousandth of an inch. It is 0.0254 mm, not one millimetre — the two units in that menu are a factor of 39 apart. If the drawing gives mils, enter mils; a millimetre figure belongs on the millimetre entry.
  • Round and polygonal shapes take a radius, not a diameter — and a side, not a width across the flats. The hexagonal prism wants the length of one side of the hexagon; across the flats that is 3 s\sqrt{3}\,s, so a bar measuring 20 mm across the flats has an 11.55 mm side. The octagon follows (1+2)s\left(1+\sqrt{2}\right)s instead. The tube is the exception: it carries both diameters and both radii and keeps them in step, so either one can be filled in first.
  • Measure the piece, not the label. Mill tolerances are small in absolute terms and large in relative terms. On 3 mm sheet, half a millimetre is 17%\,17\% of the mass, while the same error on 50 mm plate is one percent. Calipers on the actual sheet are worth more than a datasheet thickness.
  • Count identical pieces only. The multiplier applies to one shape at a time. For a mixed batch, calculate each shape separately and add the results, or use the Other prisms route with the combined material volume.

Frequently Asked Questions

Q

How do I weigh a hollow extrusion or a profile that is not in the menu?

Use Other prisms and enter the volume of material rather than the volume of the outline: multiply the cross-sectional area of the profile by its length. A profile with a 2.5 cm² section, cut 2 m long, holds 500 cm³ of aluminum:

V=2.5 cm2×200 cmV = 2.5\ \mathrm{cm^{2}} \times 200\ \mathrm{cm}==500 cm3500\ \mathrm{cm^{3}}

At 2700 kg/m³ that is 1.35 kg. The same route handles a casting with a cavity, a machined part with a pocket, or any shape where the outline and the material are not the same thing.

Q

My supplier quotes kilograms per metre. How do I use that?

Enter a one-metre length in the matching shape and read the mass: for the 50 mm by 2 mm tube above, 1 m comes out at 0.8143 kg, which is the supplier figure. Work that way round when comparing quotes, because extruded profiles are usually priced by mass per length rather than by size.

For a profile that is not in the menu, the Other prisms route gives the same number from a one-metre material volume: 2.5 cm² of section over 100 cm is 250 cm³, or 0.675 kg per metre at 2700 kg/m³.

Limitations

  • •The densities are nominal figures. Real stock varies with composition within the grade, with temper, and with mill tolerances. Expect a few percent either way, and weigh the actual piece when the number has to be exact.
  • •Shapes are assumed solid and uniform. Hollow sections, pockets, tapers, fillets and coatings need the material-volume route described in the FAQ, and an irregular or elliptical section has to be reduced to a volume somewhere else before it can be entered.
  • •The other-prisms route trusts your volume. Nothing checks how that number was obtained, so a section area in square millimetres entered as square centimetres passes straight through to the answer.
  • •Not a load rating or a structural check. Mass is only one input to handling, rigging and design decisions. Lifting limits, axle loads, shelf capacities and structural work belong to a qualified engineer working from the actual material specification and the applicable code.
  • •The molten entry is an estimate for liquid metal. 2600 kg/m³ describes aluminum while it is liquid, which is useful for melt and casting planning and wrong for a solid billet of the same grade.

For a solid rectangular block of any other material, the size to weight calculator takes the same three dimensions with a density you supply and works in both directions.

Aluminum Weight Calculator for Plates, Tubes and Cans